The complete combustion reaction for C16H34 would be as follows:
C16H34 + 17/2O2 ------> 16CO2 + 17H2O
We are given the amount of oxygen to be used for the reaction. This value would be the stating point for the calculations.
0.50 mol O2 ( 1 mol C16H34 / 17/2 mol O2 ) ( 22.4 L / 1 mol ) = 1.317 L = 1317 mL C16H34
D) carbon dioxide is the answer to your question