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3 years ago

What is this? anyone help

Mathematics

1 answer:

qwelly [4]3 years ago

4 0

Answer:

-a^2 -a -35

Step-by-step explanation:

a(4-a) -5(a+7)

Distribute

4a -a^2 -5a-35

Combine like terms

-a^2+4a -5a-35

-a^2 -a -35

You might be interested in

If 7 key chains cost $55.65, then 12 key chains cost $

Nimfa-mama [501]

Divide $55.65 by 7 to get the cost of 1 key chain ($7.95). Then multiply the cost of 1 by 12 and get $95.40

3 0

3 years ago

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago

(6) Find the area of the triangle. If you get stuck, consider drawing a rectangle

masha68 [24]

Answer:

we need the options

Step-by-step explanation:

what are the numbers

4 0

2 years ago

Select the equation in slope-intercept form that is equivalent to: 4x + 3y = 12

sattari [20]

Answer:

y = -4/3x +4

Step-by-step explanation:

y= mx+b

solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

Let's solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

3y / 3 =-4x +12 /3

y = -4/3x +4

hopes this helps you out

5 0

3 years ago

Cloud [144]

Answer: 100

Step-by-step explanation:

a) The mean of a normal distribution is also the median. Half the population will have values above the mean. Half of 200 is 100, so ...

... 100 students will have grades above 70%.

b) 84% is 14% above the mean. Each 7% is 1 standard deviation, so 14% is 2 standard deviations above the mean. The empirical rule tells you 95% of the population is within 2 standard deviations of the mean, so about 5% of students (10 students) got grades higher than 84% or lower than 56%. The normal distribution is symmetrical, so we expect about 5 students in each range.

... about 5 students will have grades above 84%.

3 0

3 years ago

What is this? anyone help​

What is this? anyone help