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rewona [7]
4 years ago
5

Nichior compared the slope of the function graphed to the slope of the linear function that has an x-intercept of 2/3 and a y-in

tercept of -1. If (x) represents the function with the smaller slope, what is the slope of f(x)? ​

Mathematics
1 answer:
marusya05 [52]4 years ago
4 0

Answer:

The slope of f(x) is 1.5

Step-by-step explanation:

step 1

Find the slope of the linear function that has an x-intercept of 2/3 and a y-intercept of -1

so

we have the points

(2/3,0) and (0,-1)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{-1-0}{0-2/3}

m=\frac{-1}{-2/3}

m=\frac{3}{2}=1.5

step 2

Find the slope of the function graphed

take the points

(0,-1) and (3,6)  approximately

substitute in the formula

m=\frac{6+1}{3-0}

m=\frac{7}{3}=2.33

step 3

we know that

f(x) represents the function with the smaller slope

The smaller slope is 1.5

therefore

The slope of f(x) is 1.5

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3 years ago
When y=-2, what kind of line does it have horizontal or vertical
Rashid [163]

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Step-by-step explanation: The equation <em>y = -2</em> can be thought of as y = 0x - 2. So our line has a slope of 0 and a y-intercept of -2.

To graph it, we start with the y-intercept, down 2 units on the y-axis. Now, if the slope of a line is 0, then the line must be flat or horizontal.

So we just draw a horizontal line through the y-intercept of -2.

In fact, when the equation of any line reads y = a number, it's graph will always be a horizontal line. For example, y = 3, y = -10, y = -8 and so on.

Image provided below.

8 0
3 years ago
Please HELP!!!!
Karolina [17]

Answer:


Step-by-step explanation:

Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.

When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.

Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?

What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!

Putting all of this together gives us:

z = |mag|*(cos(angle) + isin(angle))

= 2*cos(270°) + isin(270°)).

To verify, let's consider what cos(270°) and sin(270°) are.

If you graph cos(x) and look at 270°, you get 0.

If you graph sin(x) and look at 270°, you get -1.

So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.

3 0
3 years ago
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inn [45]

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Step-by-step explanation:

if f(x)=x^2

then f(t)=t^2

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3 years ago
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fgiga [73]

Answer: center is (-4,2) radius is 4

Step-by-step explanation:

Equation of circle

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3 years ago
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