Answer:
a) 279 b)254
Step-by-step explanation:
Mean = 269 days
standard deviation = 8 days
let n be the pregnancy lenght.
using normal distribution formula
z = (n – mean)/ standard deviation
n = z * standard deviation + mean
Now, z values for the top 12% has to be found using a z table.
The top 12% means 88% of area under the curve. In this case z = 1,176
n = 1,176 * 8 + 269
n = 278.4 = 279
The bottom 3% means 97% of area under the curve. In this case z = -1,882
n = -1,882 * 8 + 269
n = 253.94 = 254
We know that
if the club includes one set of identical
triplets wearing matching clothes
then
the number of different arrangements that are
possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
<span>604,800</span>
Answer:
136+ m ≥ 189 is the required inequality : m: The earning in 4th week
Arthur needs to earn AT LEAST $53 in the fourth week to buy the coat which costs at least $189.
Step-by-step explanation:
The amount earned by Arthur in first 3 weeks = $136
The amount needed to buy a coat = AT LEAST $189
Let us assume the amount Arthur needs to earn more to buy coat = $m
⇒ $ 136 + Amount Earned in 4th week ≥ $189
⇒ 136+ m ≥ 189
The above equation is the NEEDED inequality of the given situation.
Now, solving for the value of m, we get:
136+ m ≥ 189
⇒ m ≥ 189 - 136 = 53
or, m ≥ $53
Hence, Arthur needs to earn AT LEAST $53 in the fourth week to buy the coat which costs at least 189.
Answer:
The answer to your question is
a) Poster width = 3 in
lenght = 9 in
b) banner
width = 2 in
lenght = 10 in
Step-by-step explanation:
a) For the poster
width = x
lenght = 3x
Perimeter of a rectangle = 2base + 2 height
= 2(x) + 2(3x) = 24
2x + 6x = 24
8x = 24
x = 24/8
x = 3
width = 3 in
lenght = 3(3) = 9 in
b) For the banner
width = y
lenght = 5y
Perimeter of a banner = 2 base + 2 height
2 (y) + 2(5y) = 24
2y + 10y = 24
12y = 24
y = 24/12
y = 2
width = 2 in
lenght = 5(2) = 10 in
