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3 years ago

What angle relationship describes VQR and QRW?

Mathematics

1 answer:

Vlad [161]3 years ago

8 0

Answer: alternate interior angles

Step-by-step explanation:

Got it Right on the test. :)

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Y=7x+8 can somebody help me

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What’s the question ? do you need the slope or the y intercept ?

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2 years ago

How do i solve this? i need help

Korvikt [17]

A (103)(109)

=103*109

=(10*10*10)*(10*10*10*10*10*10*10*10*10)

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=1012

=1000000000000

c.1e+23

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3 years ago

What is m in the simultaneous equation <br> M -n=1<br><br> M+n=3

Lady bird [3.3K]

The simultaneous equations is missing +8

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2 years ago

Read 2 more answers

What is the answer to this problem 1/2=q 2/3?

Angelina_Jolie [31]

3/2 = 2q
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3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago