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3 years ago

Given: △ACE, BD∥AE Prove: BA/CB=DE/CD Drag

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE

Triangle AED ||| BDE Angle angle congruent

... By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

AlladinOne [14]3 years ago

4 0

Answer:

Corresponding Angle Postulate.

ACE - BCD.

Segment Addition Postulate

Step-by-step explanation:

I can confirm that these answers are correct! :D

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Which expression is equivalent to 15x – 2(3x + 6)?

lakkis [162]

Answer:

35x+12

Step-by-step explanation:

1. You combine like terms. (15x *3x=35x)

2.You Multiply other terms (2*6= 12)

3. Answer: 35x+12

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3 years ago

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3 years ago

Read 2 more answers

A grading machine can grade 48 tests in 1 minute. How

S_A_V [24]

$\bf \begin{array}{ccll}
tests&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
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3 years ago

Write a quadratic function f(x) for the area of a rectangle length x+5 width 3x-7

Semmy [17]

The area of a rectangle is the product of its length and width.
$l=x+5 \\
w=3x-7 \\ \\
A=lw=(x+5)(3x-7)=3x^2-7x+15x-35=3x^2+8x-35 \\ \\
\boxed{f(x)=3x^2+8x-35}$

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3 years ago

Find the indicated values g(t)=t^2-t and f(x)=1+x g(f(2)+3)

Semmy [17]

Answer:

g( f(2)+3) = 30

Step-by-step explanation:

step(i):-

Given function g(t)=t²-t and f(x)=1+x

given f(x)=1+x

f(2) = 1 + 2 =3

step(ii):-

g( f(2)+3) = g(3 + 3)

= g(6)

= (6)² - 6

= 36 -6

= 30

Conclusion:-

g( f(2)+3) = 30

7 0

2 years ago

Given: ​△ACE, BD​∥AE Prove: BA/CB=DE/CD Drag

Given: △ACE, BD∥AE Prove: BA/CB=DE/CD Drag