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3 years ago

Given: △ACE, BD∥AE Prove: BA/CB=DE/CD Drag

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE

Triangle AED ||| BDE Angle angle congruent

... By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

AlladinOne [14]3 years ago

4 0

Answer:

Corresponding Angle Postulate.

ACE - BCD.

Segment Addition Postulate

Step-by-step explanation:

I can confirm that these answers are correct! :D

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Step-by-step explanation:

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3 years ago

Expand, answer should be a polynomial in standard form<br><br> (5a+2)(a+4)=

castortr0y [4]

Answer:

The standard form of the expression (5a+2)(a+4) is $5a^{2} + 22 a + 8$ .

Step-by-step explanation:

Here, the given expression is (5a+2)(a+4).

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= $5a^{2} + 20 a + 2a + 8$

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or, $(5a+2)(a+4) = 5a^{2} + 22 a + 8$

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Given: ​△ACE, BD​∥AE Prove: BA/CB=DE/CD Drag

Given: △ACE, BD∥AE Prove: BA/CB=DE/CD Drag