Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.
Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.
1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13
2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
Let h(t) represent the height of the projectile after t seconds. If the projectile is being launched from the ground, then h(0)=0, and h(t)=-4.9t²+98t. When the equation is in this form, the maximum height is determined by -98/2(-4.9), or after 10 seconds. Thus
-4.9(100)+98(10)=490 m as the highest point of the projectile
Then, when it hits the ground, h(t)=0, so
0=-4.9t²+98t
98t=4.9t²
4.9t=98
t=20
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Answer:

Step-by-step explanation:
Plot the figure to better understand the problem
see the attached figure
we know that
If the figure is a rectangle
then

The area of the rectangle is equal to

where
B is the base
h is the height
the base B is equal to the distance AB
the height h is equal to the distance AD
Step 1
Find the distance AB
the formula to calculate the distance between two points is equal to


substitute the values

Step 2
Find the distance AD
the formula to calculate the distance between two points is equal to


substitute the values

Step 3
Find the area of the rectangle

we have

substitute

Step-by-step explanation:
1.BEA
2.AEB
HOPE IT HELPS
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