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3 years ago

Please help! I need these done before 2 pm!

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer:

9. (7a + 6b – 9c) – (3a – 6c)

=7a+6b-9c-3a+6c

=7a-3a+6b-9c+6c

=4a+6b-3c

10. (x2 – 9) – (-2x2 + 5x – 3)

= x^2-9+2x^2-5x+3

=x^2+2x^2-5x-9+3

=3x^2-5x-6

11. (5 – 6d – d2) – (-4d – d2)

=5-6d- d^2+4d+ d^2

=5-6d+4d-d^2+ d^2

=5-2d

12. (-4x + 7) – (3x – 7)

=-4x+7-3x+7

= -4x-3x+7+7

=-7x+14

13. (4a – 3b) – (5a – 2b)

=4a-3b-5a+2b

=4a-5a-3b+2b

= -a-b

14. (2c + 3d) – (-6d – 5c)

=2c+3d+6d+5c

=2c+5c+3d+6d

=7c+9d

15. (5x2 + 6x – 9) – (x2 – 3x +7)

=5x^2+6x-9- x^2+3x-7

=5x^2- x^2+6x+3x-9-7

=4x^2+9x-16

16. (3y – 6) – (8 – 9y)

=3y-6-8+9y

=3y+9y-6-8

=12y-14

17. (3a2 – 2ab + 3b2) - (-a2 – 5ab + 3b2)

=3a^2-2ab+3b^2+ a^2+5ab-3b^2

=3a^2+ a^2-2ab+5ab+3b^2- 3b^2

=4a^2+3ab

18. 5c – [8c – (6 – 3c)]

=5c-[8c-6+3c]

=5c-8c+6-3c

=5c-8c-3c+6

= -6c+6

19. 10x + [3x – (5x – 4)]

=10x+[ 3x-5x+4]

=10x+3x-5x+4

=8x+4

20. 3x 2 – [7x- (4x – x2) + 3]

=3x^2-[7x-4x+ x^2+3]

=3x^2-7x+4x- x^2-3

=3x^2-x^2-7x+4x-3

=2x^2-3x-3

21. x2 – [ - 3x+ ( 4 – 7x)]

= x^2-[ -3x+4-7x]

= x^2+3x-4+7x

= x^2+3x+7x-4

= x^2+10x-4

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3 years ago

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3 years ago

Read 2 more answers

4/5 minus 1/3 plz i need help

IRISSAK [1]

Answer:

7/15

Step-by-step explanation:

Step 1

We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change, too. They get multiplied by the other term's denominator.

So we multiply 4 by 3, and get 12.

Then we multiply 1 by 5, and get 5.

Next we give both terms new denominators -- 5 × 3 = 15.

So now our fractions look like this:

−

Step 2

Since our denominators match, we can subtract the numerators.

12 − 5 = 7

So the answer is:

Step 3

Last of all, we need to simplify the fraction, if possible. Can it be reduced to a simpler fraction?

To find out, we try dividing it by 2...

Nope! So now we try the next greatest prime number, 3...

Nope! So now we try the next greatest prime number, 5...

Nope! So now we try the next greatest prime number, 7...

Nope! So now we try the next greatest prime number, 11...

No good. 11 is larger than 7. So we're done reducing.

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2 years ago