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Ahat [919]
3 years ago
13

An engineer needs to determine the distance across a river without swimming to the other side. The engineer notices a tree on th

e other side of the river and suddenly has an idea.
Describe how she will sketch her idea to be able to determine the distance. Make a sketch and support you figure by number use meter as unit.
Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

Step-by-step explanation:

The engineer can use a clinometer to measure the angle of elevation of the top of the tree. Let the height of the tree be represented by x, the she could determine the distance across the river, d, by applying the trigonometric function.

Tan θ = \frac{opposite}{adjacent}

           = \frac{x}{d}

the the distance, d = x ÷ Tan θ

Assume the angle of elevation of the top of the tree is 30^{o}, and the height of the tree is 10 m, then the distance, d, across the river would be;

d = \frac{10}{0.5774}

  = 17.3190

d = 17.32 m

The sketch to the explanation is attached to this answer for more clarification.

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In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and m\angle BCD=30^\circ.

To find:

The m\angle AOB.

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

\angle OBA\cong \angle BCD        [Alternate interior angles]

m\angle OBA=m\angle BCD

m\angle OBA=30^\circ

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

The base angles of an isosceles triangle are congruent. So,

\angle OAB\cong \angle OBA      [Base angles of an isosceles triangle]

m\angle OAB=m\angle OBA

m\angle OAB=30^\circ

Using the angle sum property in triangle AOB, we get

m\angle OAB+m\angle OBA+m\angle AOB=180^\circ

30^\circ+30^\circ+m\angle AOB=180^\circ

60^\circ+m\angle AOB=180^\circ

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m\angle AOB=120^\circ

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3 years ago
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Answer:

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3 years ago
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Igoryamba
Given the graph y = f(x)

The graph y = f(cx), where c is a constant is refered to as horizontal stretch/compression

A horizontal stretching is the stretching of the graph away from the y-axis. A horizontal compression is the squeezing of the graph towards the y-axis.  A compression is a stretch by a factor less than 1.

If | c | < 1 (a fraction between 0 and 1), then the graph is stretched horizontally by a factor of c units.
If | c | > 1, then the graph is compressed horizontally by a factor of c units.

For values of c that are negative, then the horizontal compression or horizontal stretching of the graph is followed by a reflection across the y-axis.


The graph y = cf(x), where c is a constant is referred to as a vertical stretching/compression.

A vertical streching is the stretching of the graph away from the x-axis. A vertical compression is the squeezing of the graph towards the x-axis. A compression is a stretch by a factor less than 1.

If | c | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of c units.
If | c | > 1, then the graph is stretched vertically by a factor of c units.

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Step-by-step explanation:

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<h3>How to Solve a Right Triangle Using Trigonometry Ratio</h3>

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Thus, applying the Trigonometry ratio, CAH, the missing side is, x = 1.9.

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