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marissa [1.9K]
2 years ago
14

HELPPPP FOR BRAINLIEST AND FAT POINTS!!!!! PIECEWISE FUNCTION

Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
8 0

Answer:

f(1) = -3

f(-4) = -11

f(6) = 0

padilas [110]2 years ago
6 0
Find where your inputs make sense.
For the first problem it asks to find the input of f(1), the second constraint would be correct because 1 is less than for 4 and negative 2. Then you would plug in your values.
So -3(1)=-3
The second one fits the constraints of the first so plug it in for 2x-3. You would get 2(-4)-3, which equals -11
For the last one find what value corresponds to the input value of 6 and then plug it in.
6/6 -1 =0
Hope this helped you understand.
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zahra has paper rectangles of different sizes. every rectangle is 5 cm longer than it is wide. Is there a proportional relations
Vinil7 [7]

As given Zahra has paper rectangles of different sizes.

Also, Every rectangle is 5 cm is longer than it's breadth.

So, if Length=L, then Breadth= L- 5

Or , if Breadth= B, then Length= B+5

or, if length is x and breadth is y ,then writing in terms of equation

→x=y+5

As you can see,there is not any proportional relationship between length and widths of these rectangles.

3 0
3 years ago
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lesya692 [45]

First of all, we need to know what a function is.

A function is a binary relation between two sets that

8 0
11 months ago
3.4 mi/h converted into ft/sec<br><br> Please someone help me out on this question!
Vlad [161]

To convert mi/h to ft/sec, multiply it to 1.466.

So 3.4 mi/h x 1.466 = 4.986 ft/sec

5 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Anvisha [2.4K]

Step-by-step explanation:

\displaystyle y = Asec(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.

I am joyous to assist you anytime.

3 0
3 years ago
5+6 Lol I wanna help.
kati45 [8]

Answer:

11

Step-by-step explanation:

5+6 = 11

6 0
3 years ago
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