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3 years ago

Me ayudan porfa? UnU

Mathematics

2 answers:

QveST [7]3 years ago

6 0

Answer:

No lo se, lo siento. Espero que tengas la respuesta correcta

Step-by-step explanation:

Buena suerte con las pruebas futuras y que tengas un buen día.

professor190 [17]3 years ago

4 0

Answer:

c maybe 20

d maybe 33

and i dont know the last one

hola si esto está mal lo siento pero hice mi mejor esfuerzo y feliz gracias dando adiós que tengas un día bendito!

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The table shows the number of volleyballs that fit into a given number of containers. Each container holds the same number of ba

ss7ja [257]

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Step-by-step explanation:

It's a 1 : 3 ratio so the answer should be 7

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3 years ago

Given that when x is reduced by 17% the answer is y, express x in terms of y.

Dima020 [189]

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3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

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2 years ago

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4 years ago

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Midpoint has form of,

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