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3 years ago

it is always helpful to rewrite an equation in standard form as a first step in solving it, true or flase

Mathematics

2 answers:

tiny-mole [99]3 years ago

4 0

False- answer hope it helps

nignag [31]3 years ago

3 0

Answer:

The answer is false.

Step-by-step explanation:

It is always helpful to rewrite an equation in standard form as a first step in solving it. This is false.

The elimination technique works for the addition and subtraction of equations. For solving linear equations given in slope intercept form, we simply equate the 'y' and solve for 'x'. Then finding y is easy.

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you invest 2,600 in an account that pays an interest rate of 8.5% compounded continuously. Calculate the balance of your account

soldier1979 [14.2K]

The formula is
A=p e^rt
A future value?
P present value 2600
R interest rate 0.085
T time 5years
E constant
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Assume that f(1000)=50 , and it's also true that the cost to the consumer of each item is $5, did the retailer make wise use of

andriy [413]

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3 years ago

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3 years ago

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Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

$\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx$

Let $f(x) = \sqrt{1 + x^3}$ . Compute the inverse:

$f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}$

and we immediately notice that $f^{-1}(x+1)=\sqrt[3]{x^2+2x}$ .

So, we can write the given integral as

$\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx$

Splitting up terms and replacing $x \to x-1$ in the first integral, we get

$\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}$

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2 years ago

What is the range of the function on the graphe

Natasha_Volkova [10]

Answer:

hopefully helps

Step-by-step explanation:

you have to subtract the little number from the big number

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3 years ago