Answer:

Step-by-step explanation:
The <u>width</u> of a square is its <u>side length</u>.
The <u>width</u> of a circle is its <u>diameter</u>.
Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.
<u>Formulas</u>



If the diameter is equal to the side length of the square, then:

Therefore:

So the ratio of the area of the circle to the original square is:

Given:
- side length (s) = 6 in
- radius (r) = 6 ÷ 2 = 3 in


Ratio of circle to square:

C. 135
Corresponding parts of congruent figures are the same
Answer:

Step-by-step explanation:
Let
and
. Now we evaluate the given function at
:
(1)



Which means that
is less than the y-component of A. Therefore, the right answer is
.
I believe it’s A.
good luck!!
Let x = amount of mortgage (aka the amount by the bank)
25% of the monthly income of $3000 is 0.25*3000 = 750 dollars
So using this rule, the family can pay up to $750 per month on mortgage
1% of the amount loaned (x) is equal to this figure, so
0.01*x = 750
0.01*x/0.01 = 750/0.01
x = 75000
Therefore, the most expensive mortgage this family can afford is $75,000. Anything higher and they go over budget.