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Stella [2.4K]
3 years ago
6

Solve for x-8+6(-x-3)+4x​

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

-x-26                                             This is the answer

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A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 60 dumpster loads of
Lana71 [14]

Answer:

f(x) = -4x + 80

Step-by-step explanation:

You are given two points,

(5, 60) and (10, 40)

in order to get the equation, let's use the form slope-intercept form

m = (y1 - y2) / (x1 - x2)

m = (60 - 40) / (5 - 10)

m = 20/-5

m = -4

Get the x intercept

y = mx + b

60 = (-4)(5) + b

b = 60+20

b = 80

so the equation is

y = -4x + 80

f(x) = -4x + 80

5 0
3 years ago
Ned and Jack are each saving money for a new smartphone. Ned initially has $65 and plans to save $5.50 per week. Jack does not h
julia-pushkina [17]

Answer:

I'm not sure exactly what you're looking but I would set up the equation like this.

y=65+5.5x   for Ned's equation

y=8.75x       for Jack's equation.

Step-by-step explanation:

This is in y=mx+b format, hopefully it helps!

7 0
3 years ago
I need help with this question
Tamiku [17]

Answer:

4

Step-by-step explanation:

Go to where it says -8 on the y-axis then rise 4 and run 1

6 0
3 years ago
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The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
3 years ago
The green line below
kenny6666 [7]

Answer:

B, C, D, & E

Step-by-step explanation:

All lines intersect the x axis and y axis so we know B and D are correct. All graphs are in the xy plane unless i (\sqrt{-1}) is involved, or C. It crosses the center (origin) of the entire plane so it crosses the origin, or E.

3 0
4 years ago
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