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3 years ago

Slope Intercept Form y=mx+b How can I explore it? It's for a presentation, please help

Mathematics

2 answers:

Mkey [24]3 years ago

8 0

Answer:

I don't understand the question.

Step-by-step explanation:

I don't know how to explore the slope intercept line equation.

However, 'b' is the y axis intercept (the point where is crosses the y axis and 'm' is the slope of the line. The 'm' and the 'b' can be positive or negative numbers.

A positive 'm' is a line that goes 'up' (the y value increases from the left to right) and a negative 'm' is a line that goes 'down' (the y value decreases from left to right).

lidiya [134]3 years ago

6 0

Answer:

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Find the slope of the line that passes through the points (5,9) and (2,7).

lozanna [386]

2/3 is the correct answer for a line passing through the stated coordinates:)

7 0

3 years ago

Read 2 more answers

Simplify the first expression 5(m+1)-1=

Olegator [25]

Answer:

-0.8/ -4/5

Step-by-step explanation:

5(m+1) -1 = 0

5m +5 -1 = 0

5m +4 =0

5m= -4

m= -4/5

8 0

3 years ago

I need help plzzzz!!!!!!!!:)

Mila [183]

Answer:

B: y = -2/3x - 10/3

Step-by-step explanation:

The point is at (-2,-2), therefore when you input -2 into the desired equation, it should yield -2 as our output. If we use the equation B, the equation becomes

-4/3 - 10/3 which is -6/3. After dividing it we get -2 as the output.

To find the line yourself we use the point slope formula

y - y1 = m(x - x1)

The line is parallel to the one on the graph so the slope or m is equal to -2/3

We input the coordinates we want for y1 and x1.

y - (-2) = -2/3 (x - (-2))

y + 2 = -2/3x - 4/3

y + 6/3 = -2/3x - 4/3

y = -2/3x - 10/3

3 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE WRITE A EQUATION OF THIS LINE!!

serious [3.7K]

Answer (assuming it can be in slope-intercept form):

y = -x - 1

Step-by-step explanation:

When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . I chose the points (0, -1) and (-1, 0):

$m = \frac{(0)-(-1)}{(-1)-(0)} \\m = \frac{0+1}{-1-0} \\m = \frac{1}{-1} \\m = -1$

Thus, the slope is -1.

2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.

3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:

$y = -x -1$