when it tells you what R is then you show a number line with -4 less then R
F(x) = x^2 + 1
f(4) = 4^2 + 1 = 16 + 1 = 17
2*f(4) = 2 * 16 = 32
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Answer:
I think it volume will be 234m3
1. slope of the given line = 1/5
the equation is
(y-2)/(x-(-2))=1/5
x+2=5y-10
x-5y+12=0
2. slope of the given line = -1/6
the equation is
(y-9)/x=6
y-9=6x
y=6x+9