-5n - 3 - 3 > 19
-5n - 6 > 19
+ 6 +6
-5n > 25
divide by -5 on each side
change signs since dividing by negative

N< -5

For graphing on the line, you will create an OPEN circle on -5 and sketch it to the left.

3 0

3 years ago

Due tonight<br>Please help!!!!!

Harrizon [31]

angle BGC and angle BAD

7 0

3 years ago

The shaded sector above covers 1/3 of the circle. If the radius of the circle above is 3 cm, what is the area of the sector in t

Mekhanik [1.2K]

Given:

The shaded sector above covers $\dfrac{1}{3}$ of the circle.

Radius of the circle = 3 cm

To find:

The area of the sector in terms of π.

Solution:

The area of a circle is

$A=\pi r^2$

Substituting $r=3$ , we get

$A=\pi (3)^2$

$A=9\pi$

It is given that the shaded sector above covers $\dfrac{1}{3}$ of the circle.

The area of shaded sector $=\dfrac{1}{3}A$

$=\dfrac{1}{3}(9\pi)$

$=3\pi$

Therefore, the area of shaded sector is 3π sq. cm.

5 0

3 years ago