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Ksenya-84 [330]
1 year ago
6

Determine if the given measurements can construct a triangle?11,11,11- Yes, this forms a triangle.-No, this DOES NOT form a tria

ngle.
Mathematics
1 answer:
Harman [31]1 year ago
7 0

ANSWER

Yes, this forms a triangle

EXPLANATION

We want to check if the measurements 11, 11 and 11 can make the side of a triangle.

We will use the Triangle Inequality Theorem.

We have to check if the sum of any of the two measurements will be greater than the third. If yes, then, they can form a triangle and vice versa.

That is:

11 + 11 = 22

Since 22 is greater than 11, the measurements can form a triangle.

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Solve ax + b = cx + d for x.
romanna [79]

Answer: X = (d-b) / (a-c)

This way this worded is weird but I think I got it

Step-by-step explanation:

Subtract B from both sides

ax = cx +d -b

Then subtract CX from both sides

ax -cx =d-b

Distributive Property

x(a-c) =d-b

Divide both sides by a-c

X = (d-b) / (a-c)

6 0
3 years ago
Keisha just deposited a total of 900 into savings accounts at two different banks. the 550 she deposited at bank A will earn 2.2
mars1129 [50]

Answer:

F.

Step-by-step explanation:

Find how much interest she will earn from bank A:

100% = 550

1% = 550 ÷ 100 = 5.5

2.25% = 12.375

Find how much interest she will earn from bank B:

900 - 550 = 350

100% = 350

1% = 350 ÷ 100 = 3.5

3% = 3.5 x 3 = 10.5

Find out how much money she will earn from both banks of their interest:

10.5 + 12.375 = 22.875

Find out how much money she will earn from both banks of their interest in 2 years:

22.875 x 2 = 45.75

Find out how much she earns from both banks including interest:

900 + 45.75 = 945.75

(Final answer)

5 0
2 years ago
What is 38.3 Million out of 235.7 million of a percentage?
masha68 [24]

Answer:

The answer is 6.15404699739

Step-by-step explanation:


5 0
3 years ago
Rewrite 9cos 4x in terms of cos x.
rosijanka [135]
\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
72cos^4(x)-72cos^2(x)+9


---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
-------------------------------\\\\

\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[  \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
\\\\\\
2\left[  \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
\\\\\\

\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}
4 0
3 years ago
Kyle stood on a bridge and threw a rock up and over the side. The height of the rocks in meters can be approximated by approxima
mojhsa [17]

Answer:

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747)

Step-by-step explanation:

The given expression is -5·t² + 5·t + 24

To factorize the expression by completing the square method, we equate the expression to zero to get;

-5·t² + 5·t + 24 = 0

WE divide by -5 to get;

t² - t - 24/5 = 0

t² - t = 24/5

t² - t + 1/4 = 24/5 + 1/4

(t - 1/2)² = 5.05

t - 1/2 = ±√5.05

t = 1/2 + √5.05, 1/2 - √5.05

The factorized expression becomes;

(t - 1/2 + √5.05) and (t - 1/2 - √5.05)

Which gives;

(t - 2.747) ×(t - 1.747)

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747).

8 0
3 years ago
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