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Slav-nsk [51]
3 years ago
15

2v=x+40t solve for v​

Mathematics
1 answer:
spin [16.1K]3 years ago
6 0

Answer:

v=1/2x+20t

you have to divide both sides by 2 to isolate the variable

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Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what
Ksju [112]
y=mx+b \\ \\
(x,y)=(-4,-5) \hbox{ and } (x,y)=(-6,3) \\ \Downarrow \\
-5=-4m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \times (-3) \\
3=-6m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times 2 \\ \\
15=12m-3b \\
\underline{6=-12m+2b} \\
21=-b \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\times (-1) \\
\boxed{b=-21}

The value of b is -21.
4 0
3 years ago
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A=2/b+3c ; solve for c
Artyom0805 [142]

Answer:

It is straightforward.

Answer is c= a/3 - 2/3b

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3 years ago
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BD bisects ABC. Find the value of x.
yuradex [85]
90-52=38

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6 0
2 years ago
A trapezoid has a height of 3 meters, a base length of 8 meters, and an area of 30 square meters. What is the length of the base
algol [13]

Answer:

Length of the second base will be 12 meters.

Step-by-step explanation:

Area of a trapezoid is given by the formula,

Area = \frac{1}{2}(b_1+b_2)h

Here, b₁ and b₂ are the bases of the trapezoid and 'h' is the vertical distance between the bases.

By substituting the values in the formula,

30=\frac{1}{2}(8+b_2)3

60=3(8+b_2)

20=8+b_2

b_2=12

Therefore, length of the second base will be 12 meters.

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3 years ago
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It has a slope of 0

Step-by-step explanation:

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