Question

10 POINTS. 1/7 written as a decimal is 0.142857 (this sequence repeats). What digit occurs in the 2012th spot after the decimal? Please explain.

Answer 1

1/7 = 0.142857142857142857142857142857142857142857142857142857 and so on

the pattern repeats

the first digit is 1
second digit is 4
third digit is 2
fourth digit is 8
fifth digit is 5
sixth digit is 7

and then the seventh digit is 1, and it repeats

so the six digits repeat again and again...

2012/6 = 335 2/6

It has a remainder of 2, which means that the 12th digit will be 4. because that is the second digit. After going 335 times the 6 digit patterns it will stop at the second digit which is 4.

Your answer is 4.

I hope you understood, it was kind of hard to explain :P