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2 years ago

Solve the system by adding. Drag and drop numbers into the coordinates to complete the ordered pair.

Mathematics

2 answers:

Mademuasel [1]2 years ago

8 0

Answer:

(-3,5)

Step-by-step explanation:

4x + 3y = 3

x − 3y = −18

Solve by addition/Elimination

x = -3

y = 5

So,

The solution of the system is (-3,5).

HELPPP PLZZ (I got you)

jeka942 years ago

6 0

Answer: x = 4 , y = 6

Step-by-step explanation:

4 x = 3 y − 2 , 18 = 3 x + y

Solve for y

in the second equation.

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4 x = 3 y − 2 y = 18 − 3 x

Replace all occurrences of

y in 4 x = 3 y − 2

with

18 − 3 x . 4 x = 3 ( 18 − 3 x ) − 2 y = 18 − 3 x

Simplify

3 ( 18 − 3 x ) − 2

Tap for more steps...

4 x = − 9 x+ 52 y = 18 − 3 x

Move all terms in

4 x = − 9 x + 52

to the left side and simplify.

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13 x − 52 = 0 y = 18 − 3 x

Solve for x

in the first equation.

Tap for more steps...

x = 4 y = 18 − 3 x

Replace all occurrences of

x in y = 18 − 3 x

with 4 . x = 4 y = 18 − 3 ⋅ 4

Simplify

18− 3 ⋅ 4

Tap for more steps...

x = 4 y = 6

The solution to the system of equations can be represented as a point.

( 4 , 6 )

The result can be shown in multiple forms.

Point Form:

( 4 , 6 )

Equation Form:

x = 4 , y = 6

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The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

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