Ask question

Ask question

All categories

3 years ago

9

X + 5x + 6 A. (x - 3)(x+3) OB. (x - 1)(x+6) OC. (x+3)(x + 2) D. (x + 5)(x + 1)

1 answer:

il63 [147K]3 years ago

4 0

The answer is : C. (X+3)(X+2)

You might be interested in

A building is 4,500 feet tall while the scale model of the mountain is 15 inches tall. What is the scale factor?

Natasha_Volkova [10]

Answer:

I think it is 300.

Step-by-step explanation:

5 0

3 years ago

What is the value of y ?

Maksim231197 [3]

The answer is 6 to your question, but why does my answer have to be at least 20 characters long?

8 0

3 years ago

Solve for the inverse of: f(x)=1/8(x+1)^3

lara31 [8.8K]

Answer: $y=(8x)^{\frac{1}{3}} -1$ or $y=\sqrt[3]{8x} -1$

Step-by-step explanation:

To find the inverse, you switch y with x and x with y. Then, you solve for y.

$y=\frac{1}{8} (x+1)^3$ [switch y with x and x with y]

$x=\frac{1}{8} (y+1)^3$ [multiply both sides by 8]

$8x=(y+1)^3$ [cube both sides]

$\sqrt[3]{8x} =y+1$ [subtract both sides by 1]

$y=\sqrt[3]{8x} -1$ or $y=(8x)^{\frac{1}{3}} -1$

6 0

3 years ago

Please Explain it- Math

Kipish [7]

Answer:

It is a horizontal line. The slope = 0.

The line cuts the y-axis at the point

(0,9)

Step-by-step explanation:

y=9

is the equation of a horizontal line. The slope is 0.

If we write it in slope-intercept form we will have:

y=0x+9

This means that for any value of x

that is chosen, the y-value is always 9 Hence y

x=9.

The y-intercept is at the point

(0,9)

5 0

3 years ago

Solve the problem.A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course. At that t

Mice21 [21]

Given:

A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course.

The distance between plan and mountain is 10 km.

A short time later, the bearing to the mountain becomes 45°.

Here NM is the distance between the plane from the mountain when the second bearing is taken.

We need to find the measure of NM.

$We\text{ know that }\angle INM\text{ and }\angle\text{XNM are supplementary angles.}$

The sum of the supplementary angles is 180 degrees.

$\angle INM+\angle XNM=180^o$ $\text{Substitute }\angle XNM=45^o\text{ in the equation.}$

$\angle INM+45^o=180^o$

$\angle INM=180^o-45^o$

$\angle INM=135^o$

We know that the sum of all three angles of the triangle is 180 degrees.

$\angle INM+\angle NIM+\angle INM=180^o$ $\text{Substitute }\angle INM=135^o\text{ and }\angle NIM=35^o\text{ in the equation.}$

$135^o+35^o+\angle INM=180^o$

$170^o+\angle INM=180^o$

$\angle INM=180^o-170^o$

$\angle INM=10^o$

Consider the sine law.

$\frac{\sin N}{IM}=\frac{\sin M}{IN}=\frac{\sin I}{NM}$

Take the equation to find the measure of NM.

$\frac{\sin N}{IM}=\frac{\sin I}{NM}$ $\text{Substitute }\angle N=135^o,\angle I=35^o,\text{ and IM=10 in the equation.}$

$\frac{\sin 135^o}{10}=\frac{\sin35^o}{NM}$

$NM=\frac{\sin 35^o}{\sin 135^o}\times10$ $NM=8.11$

Hence the measure of NM is 8.1 km.

The plane is 8.1 km far from the mountain when the second bearing is taken.

5 0

1 year ago