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aleksklad [387]

2 years ago

8

Given that

="c=\frac{2d+1}{3d-1}" align="absmiddle" class="latex-formula">,
1. calculate the value of c when d = $\frac{1}{4}$
2. express d in terms of c

1 answer:

nata0808 [166]2 years ago

7 0

Answer:

C = -6

Step-by-step explanation:

C = [2×1/4 + 1] ÷ [3×1/4 -1 ]

C = 3/2 ÷ -1/4

C = 3/2 × -4 = -6

C = 2d + 1 / 3d - 1

So, d = ( C + 1 ) / ( 3C - 2 )

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creativ13 [48]

Answer:

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Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

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If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

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3 years ago

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Answer:

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