Answer:
<h2> d = 8.9</h2>Step-by-step explanation:
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We will use seperation of variables
tmes both sies by 1/(y^2)
times both sides by dx
we get
1/(y^2)dy=1/(x^3)dx
integrate both sides
-1/y=1/(2x^2)+c
initial condition, (1,1)
-1/1=1/(2(1^2))+c
-1=1/2+c
-3/2=c
-1/y=1/(2x^2)-3/2
solve for y
-1=y(1/(2x^2)-3/2)
y=-1/(1/2x^2-3/2)
tmes both sies by 1/(y^2)
times both sides by dx
we get
1/(y^2)dy=1/(x^3)dx
integrate both sides
-1/y=1/(2x^2)+c
initial condition, (1,1)
-1/1=1/(2(1^2))+c
-1=1/2+c
-3/2=c
-1/y=1/(2x^2)-3/2
solve for y
-1=y(1/(2x^2)-3/2)
y=-1/(1/2x^2-3/2)
Answer: ∠1 = 109° ∠2 = 71°
<u>Step-by-step explanation:</u>
If the two angles form a linear pair, then their sum is 180°
∠1 + ∠2 = 180°
(5x + 9) + (3x + 11) = 180
8x + 20 = 180
8x = 160
x = 20
∠1 = 5x + 9
= 5(20) + 9
= 100 + 9
= 109
∠2 = 3x + 11
= 3(20) + 11
= 60 + 11
= 71
<u> CHECK:</u>
∠1 + ∠2 = 180°
109° + 71° = 180°
180° = 180°