Lisa, Juan and isaac equally shared 1/2 of a cake which fraction of the whole cake did each of them recieve

Mathematics

1 answer:

IgorLugansk [536]2 years ago

6 0

Answer:

Each will receive $\frac{1}{6}th$ of the cake.

Step-by-step explanation:

Let the amount of cake = c

Lisa, Juan and Isaac are the persons who are sharing half of a cake equally.

Number of persons = 3

Part of the cake shared = $\frac{c}{2}$

Fraction of the cake shared by each = $\frac{\text{Amount of cake shared}}{\text{Number of persons who shared}}$

= $\frac{\frac{1}{2}c}{3}$

= $\frac{1}{6}c$

Therefore, fraction of total cake shared by each member will be $\frac{1}{6}$ of the total amount of cake.

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What is the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice?

Vladimir [108]

For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).

Thus, there are 16 possible sums when three six-sided dice are rolled.

Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.

The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.

That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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4 0

3 years ago

(05.06)

Ymorist [56]

the answer for this question is (B) 5,-2

7 0

3 years ago

SOMEONE PLEASE HELP!!

german

$-12=\dfrac{-12}{1}=\dfrac{12}{-1}=\dfrac{-24}{2}=\dfrac{24}{-2}=\dfrac{-36}{3}=\dfrac{36}{-3}=\dfrac{-48}{4}=\dfrac{48}{-4}=\dots$