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DaniilM [7]
3 years ago
13

X - (.0765*X) = 554.10

Mathematics
2 answers:
erastova [34]3 years ago
6 0

Answer:

X = 600

Step-by-step explanation:

x-(0.0765x)=554.1

x-0.0765x=554.1

0.9235x=554.1

x=600

:/

stealth61 [152]3 years ago
6 0
The answer is 600 let me know if u want the explanation
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A company makes windows for use in homes and commercial buildings. The standards for glass thickness call for the glass to avera
guajiro [1.7K]

The question is incomplete. The complete question follows.

A company makes windows for use in homes and commercial builidings. The standards for glass thickness call for the glass to average 0.325 inch with a standard deviation equal to 0.065 inch. Suppose a random sample of n=44 windows yield a sample mean of 0.337 inch. Complete parts a and b.

a. What is the probability of x ≥ 0.337 if the windows meet the standards?

b. Based on your answer to part a, what would you conclude about the population of windows? Is it meeting the standards? (A result is unusual if it has a probability less than 0.05)

Answer and Step-by-step explanation: To answer this question, use <u><em>Central Limit Theorem</em></u>: it states regardless of the original population distribution, if the sample size is large enough, the sample mean distribution will approach a normal distribution.

The calculations for the CLT is given by normalizing the distribution, i.e.:

z=\frac{x-\mu}{\sigma/\sqrt{n} }

where

z is z-score

x is the sample mean

μ is population mean

σ is standard deviation of the population

n is the number of individuals in the sample

Calculating z-score for the window maker company:

z=\frac{0.337-0.325}{0.065/\sqrt{44} }

z=\frac{0.012}{0.0098}

z = 1.22

Using the z-score table, we found the probability:

P = 0.8888

As it is a "more than situation":

P(x≥0.337) = 1 - 0.8888

P(x≥0.337) = 0.1112  or 11.12%

a. Probability of x≥0.337 if the windows meet the standards is 11.12%.

b. Comparing results, probability of x≥0.337 is bigger than 0.05:

0.1112 > 0.05

So, we can conclude that the random sample of n=44 is meeting the standards estipulated.

7 0
3 years ago
402 = 2 x 3 x ____<br> help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Westkost [7]

Answer:

67

Step-by-step explanation:

2x3=6

402/6=67

2x3x67=402

hope this helped:)

5 0
3 years ago
That sounds like a good deal, but how about I give you 10 points for an answer.
Ilia_Sergeevich [38]
The answer is A - 1
Hope it helped
3 0
3 years ago
Read 2 more answers
Find the volume and surface area of the composite figure. Give your answer in terms of π.
irakobra [83]

Answer:

V = 240π cm^3 , S= 168π cm^2

Step-by-step explanation:

The given figure is a combination of hemi-sphere and a cone

<u>Volume:</u>

For volume

r = 6 cm

h = 8 cm

Volume\ of\ cone = \frac{1}{3}\pi r^2h\\= \frac{1}{3}\pi (6)^2*8\\=\frac{1}{3}\pi *36*8\\=\frac{288}{3}\pi\\=96\pi cm^3 \\\\Volume\ of\ hemisphere = \frac{2}{3}\pi r^3\\=\frac{2}{3}*\pi * (6)^3\\=\frac{2}{3}*\pi *216\\=\frac{432}{3}\\=144\pi cm^3 \\\\Total\ Volume= Volume\ of\ cone + Volume\ of\ hemisphere\\= 96\pi +144\pi \\=240\pi cm^3

<u>Surface Area:</u>

For this particular figure we have to consider the lateral area of the cone shape and surface area of the hemisphere

We have to find the lateral height

l = \sqrt{r^2+h^2}\\ l = \sqrt{(6)^2+(8)^2} \\l= \sqrt{36+64}\\ l = \sqrt{100}\\l = 10cm\\\\Surface\ area\ of\ cone = \pi rl\\= \pi (6)(10)\\=\pi *60\\=60 \pi\ cm^2\\\\Surface\ area\ of\ hemisphere = 2\pi r^2\\= 2 \pi * (6)\\= 2 \pi *36\\= 72 \pi\ cm^2\\\\Total\ surface\ Area = Surface\ area\ of\ cone + Surface\ area\ of \ hemisphere\\= 60 \pi + 72 \pi\\=132 \pi\ cm^2

Hence the first option is correct ..

3 0
3 years ago
A/20 + 14/15 = 9/15 <br><br> Can i get some help?
KiRa [710]
Method 1:

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}

Method 2.

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}
3 0
3 years ago
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