I hope this helps you
2a.2a+1.2a-3.2a-3.1
4a^2+2a-6a-3
4a^2-4a-3
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
Answer:
<h3>
-2a³ + 9a² + 6ab² + 45a + 18b² </h3>
Step-by-step explanation:
(a + 3)×(−2a² + 15a + 6b²) =
= a×(−2a² + 15a + 6b²) + 3×(−2a² + 15a + 6b²) =
= -2a³ + <u>15a²</u> + 6ab² - <u>6a²</u> + 45a + 18b² =
= -2a³ + 9a² + 6ab² + 45a + 18b²
Answer:
x=2.7
Step-by-step explanation:
27 divided by 5 = 5.4 and 5.4 divided by 2 = 2.7
