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3 years ago

Solve the problem 5+x=8

Mathematics

2 answers:

Goshia [24]3 years ago

6 0

Answer:

x=3

Step-by-step explanation:

subtract 5 from both sides

you are left with x=3

Bumek [7]3 years ago

5 0

Answer:

x=3

Step-by-step explanation:

8-5=3

3=x

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Pia needs 2/3 yard of fabric to cover a bench. Which amount of fabric is greater than

Fudgin [204]

Answer:

5/6 and 7/9

Step-by-step explanation:

A and D are less than 2/3 so B and C is correct.

Hope this helps plz mark brainliest :D

6 0

3 years ago

What is 17/16 in simplest form

Olin [163]

It can be written as 1.0625

3 0

3 years ago

I'm not sure where to start and how to differentiate this.

Mazyrski [523]

The picture is not clear. let me assume y = (x^4)ln(x^3)

product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)

dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)

look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)

end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]

5 0

3 years ago

The points (2, 100) and (4, 105) are found on a line.

Sophie [7]

I think its c

Step-by-step explanation:

8 0

2 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago