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GarryVolchara [31]

3 years ago

10

Tickets to a movie cost five dollars for adults and three dollars for students a group of friends purchase 18 tickets for $82 ho

w many adult tickets did they buy

1 answer:

Dvinal [7]3 years ago

5 0

Answer: They purchased 14 adult tickets and 4 kids' tickets.

Step-by-step explanation:

14 x 5 = 70

3x4=12

and then add 70 plus 12 to get 82 dollars

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F(x) = 4x^2+2x+6 what is the discriminant of f? How many distinct real number zeros does f have?

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Answer:

The discriminant of f is 92, and it has no real zeros

Step-by-step explanation:

The discriminant of a quadratic is $b^2-4ac$ , where the quadratic is in the form $ax^2+bx+c$ . The discriminant of this one is therefore:

$2^2-4(4)(6)=4-96=-92$

Since the square root of a negative number is imaginary, this quadratic has no real number zeros. Hope this helps!

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Explain truth tables and how they work

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

<u>For urn 2</u>

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

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Answer:

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Step-by-step explanation:

An easy way to quickly figure it out is to find the y-intercept of the graph. So, from the graph you can see that the line cuts the y axis at -2. Therefore, as per the equation of a straight line, y=mx+c

option B shows that the y intercept is -2. Thus option B is the answer to this question.

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