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Papessa [141]
3 years ago
11

X−6>−2 solve the inequality

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0

Step-by-step explanation:

  • x-6>-2
  • x> -2+6
  • x>4

hope it helps.

hjlf3 years ago
3 0

Answer:

x>4

Step-by-step explanation:

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Three added to four times a number is equal to five less than six times the number
LiRa [457]

Answer:

C: 4

Step-by-step explanation:

4x+3=6x-5

Add five to both sides

4x+8=6x

Subtract both sides by 4x

8=2x

Divide both sides by 2

X=4

3 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for the line that is parallel to the line y = -4x + 5 and that passes through the give
aivan3 [116]

Answer:

Y=4x-27

Step-by-step explanation:

Parallel lines have the same gradient therefore it's-4

Y-5/X--8 =-4

Y-5=-4(x+8)

Y-5=-4x+-32

Y=-4x-32+5

Y=4x-27

3 0
4 years ago
There are a total sales of 2,000 dollars on Monday on Tuesday sales dropped 10% on Wednesday sales dropped another 20% compared
tatyana61 [14]
The net change would be 60%.



Hope this helps! <3


Sophia
5 0
3 years ago
Let x be the number of $75 trees and y the number of $85 trees. Which system of inequalities represents this situation?
Vikki [24]

Answer:

x+y= the #of trees

75+85=the amount of money

Step-by-step explanation:

3 0
4 years ago
Solve the equation x^6+3x^5+x^4-5x^3-6x^2-2x=0 in the real number system
koban [17]
First, pull out a factor of x.

x^6+3x^5+x^4-5x^3-6x^2-2x=x(x^5+3x^4+x^3-5x^2-6x-2)

Notice that when x=-1 (which you can arrive at via the rational root theorem), you have

(-1)^5+3(-1)^4+(-1)^3-5(-1)^2-6(-1)-2=-1+3-1-5+6-2=0

which means you can pull out a factor of x+1. Upon dividing you get

\dfrac{x^5+3x^4+x^3-5x^2-6x-2}{x+1}=x^4+2x^3-x^2-4x-2

The rational root theorem will come in handy again, suggesting that x=-1 appears a second time as a root, which means

\dfrac{x^4+2x^3-x^2-4x-2}{x+1}=x^3+x^2-2x-2

Now this is more readily factored without having to resort to the rational root theorem. You have

x^3+x^2-2x-2=x^2(x+1)-2(x+1)=(x^2-2)(x+1)

so in fact, x=-1 shows up as a root for a third time.

So, you have

x^6+3x^5+x^4-5x^3-6x^2-2x=x(x+1)^3(x^2-2)=0

Two roots are obvious, x=0 and x=-1 (with multiplicity 3). The remaining two are given by

x^2-2=0\implies x^2=2\implies x=\pm\sqrt2
3 0
4 years ago
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