I need help pls with this
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Find the equation of a line parallel to y-5=6x-10 that passes through (4,10)
❖ If lines are parallel to each other, they have the same slope.
So the slope of the line parallel to y-5=6x-10 is 6.
Now, since we're also given the point crossed by the line, we write the equation in point-slope form:-
Substitute 10 for y₁, 6 for m and 4 for x₁:-
On simplification,
Adding 10 to both sides results in:-
So we conclude that Option A is correct.
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