I need help pls with this

Universal Pet house sells vinyl doghouse and treated lumber doghouses. It takes the company 5 hours to build a vinyl doghouses a

LuckyWell [14K]

Answer:

The system of equations is :

Equation 1- $5x+2y=50$

Equation 2- $x+2y=30$

Number of vinyl doghouse = 5

Number of treated lumber doghouse =12.5

Step-by-step explanation:

Let x be the number of vinyl doghouses

y be the number of treated lumber doghouses

→If it takes the company 5 hours to build a vinyl doghouses and 2 hours to build a treated lumber doghouse. The company dedicates 50 hours every week towards assembling and painting doghouses.

Equation 1- $5x+2y=50$

→It takes an additional hour to paint each vinyl doghouse and an additional 2 hours to assemble each treated lumber doghouse. The company dedicates 30 hours every week towards assembling and paining dog houses.

Equation 2- $x+2y=30$

→When we solve these equation we get the number of vinyl doghouse and treated lumber doghouse.

Subtract equation 2 from equation 1

$5x+2y-x-2y=50-30$

$4x=20$

$x=\frac{20}{4}$

$x=5$

Put value of x in equation 2

$x+2y=30$

$5+2y=30$

$2y=25$

$y=\frac{25}{2}$

$y=12.5$

Therefore, number of vinyl doghouse = 5, number of treated lumber doghouse =12.5

4 0

3 years ago

Read 2 more answers

22 POINTS

MrRissso [65]

Answer:

5 feet

Step-by-step explanation:

In the height equation (notice the ball's horizontal distance traveled is not addressed here), each term means something.

'5' is where the ball started from, since that makes a difference where it winds up t seconds later. If you have trouble visualizing that, imagine if the ball was batted from the top of a skyscraper. It would take a lot longer to hit the ground than if you hit it from only 5 feet high off the ground!

81t means the ball was hit with enough force to give it an initial upward velocity of 81 feet per unit of t, as it travels forward, so that's 81 feet per second. (Depending on the angle the ball was struck, the horizontal component may be a different number.)

-16t² accounts for Earth gravity pulling the ball downward the whole time, t, the ball is in the air (the negative sign is for downward)

For 22 points, I figured you deserved a very thorough explanation.

Hope this helps!

7 0

3 years ago

The sum of the measures of the angles shown is 90°.

maria [59]

Answer:

10). 5x + (7x + 6) = 90

11). x = 7

Step-by-step explanation:

From the picture attached,

Sum of given angles measures 90°

Measures of the angles are (5x)° and (7x + 6)°

Therefore, equation to determine the values of x will be,

5x + (7x + 6) = 90

By combining similar terms of the equation,

12x + 6 = 90

12x = 90 - 6

12x = 84

x = $\frac{84}{12}$

x = 7

Therefore, by solving the equation value of x will be 7.

8 0

3 years ago

Anyone understand how to do this?

shutvik [7]

Answer:

f ( x ) = - 2x^2 + 3x + 1

Step-by-step explanation:

If f (x ) extends to → − ∞, as x→ − ∞ , provided f(x) → − ∞, as x → +∞, we can rewrite this representation as such;

− ∞ < x < ∞, while y > − ∞

Now the simplest representation of this parabola is f ( x ) = - x^2, provided it is a down - facing parabola;

If we are considering a down - facing parabola, the degree of this trinomial we should create should be even, the LCM being negative. Knowing that we can consider this equation;

Solution; f ( x ) = - 2x^2 + 3x + 1, where the degree is 2, the LCM ⇒ - 2

3 0

3 years ago

A presidential candidate's aide estimates that, among all college students, the proportion who intend to vote in the upcoming el

inessss [21]

Answer:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

Step-by-step explanation:

Assuming the following question: A presidential candidate's aide estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60% . If 127 out of a random sample of 240 college students expressed an intent to vote, can we reject the aide's estimate at the 0.1 level of significance?

Data given and notation

n=240 represent the random sample taken

X=127 represent the college students expressed an intent to vote

$\hat p=\frac{127}{240}=0.529$ estimated proportion of college students expressed an intent to vote

$p_o=0.6$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that at least 60% of students are intented to vote .:

Null hypothesis: $p \geq 0.6$

Alternative hypothesis: $p < 0.6$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

7 0

3 years ago