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34kurt
4 years ago
7

Under which conditions do you expect helium gas to deviate most from ideal behavior?

Mathematics
2 answers:
GuDViN [60]4 years ago
7 0
<span>The normal conditions of helium is 300 k and 1 atm. The conditions that deviate from the ideal behavior do not follow the ideal gas law equation PV = nRT. Among these conditions, the one that did not abide to the ideal gas equation is </span><span>b. 300 K and 2 atm with the deviation on the pressure.</span>
kherson [118]4 years ago
6 0
"300 K and 2 atm" is the condition among the conditions given in the question that you can <span>expect helium gas to deviate most from ideal behavior. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has helped you.</span>
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Apa-bear weighs 250 lb. Mama-bear weighs 50 pounds less than Papa-bear does. Their 2 cubs weigh 80 pounds each. What is the tota
o-na [289]

Given :

Apa-bear weighs 250 lb.

Mama-bear weighs 50 pounds less than Papa-bear does.

Their 2 cubs weigh 80 pounds each.

To Find :

The total weight of the Bear family .

Solution :

Weight of mama bear = 250-50\ lb=200\ lb .

Total weight is the sum of all all weight .

W=\text{Weight of papa-bear + weight of mama-bear + weight of 2 cubs}

W=250+200+2\times 80\\\\W=250+200+160\\\\W=610 \ lb

Therefore , total weight of the Bear family is 610 lb .

Hence , this is the required solution .

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3 years ago
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DENIUS [597]

Answer:

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6 0
3 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
1 year ago
Please help<br><br> Look at picture <br><br> Supplementary angles
Brilliant_brown [7]

Answer:

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Step-by-step explanation:

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BartSMP [9]

Answer:

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Step-by-step explanation:

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