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3 years ago

Under which conditions do you expect helium gas to deviate most from ideal behavior?

2 answers:

7 0

The normal conditions of helium is 300 k and 1 atm. The conditions that deviate from the ideal behavior do not follow the ideal gas law equation PV = nRT. Among these conditions, the one that did not abide to the ideal gas equation is b. 300 K and 2 atm with the deviation on the pressure.

kherson [118]3 years ago

6 0

"300 K and 2 atm" is the condition among the conditions given in the question that you can expect helium gas to deviate most from ideal behavior. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has helped you.

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Point-Slope Form *See photo*

Ne4ueva [31]

Answer:

y = 3x - 5

Step-by-step explanation:

We know that the equation 'y = 3x + ?' intersects the point (1, -2). This means that when x = 1, y = -2 in out equation above. To solve this just plug in the x and y values to get '?'.

$y = 3x + ?\\-2 = 3(1) + ?\\-5 = ?$

Now that we know '?' is -5, we write it back into slope intercept form, so our final answer is y = 3x - 5

4 0

2 years ago

Math help please =)

a_sh-v [17]

2x - 3 < 11 or 8x -10 < 82: X < 23/2

Part 1
2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2 / 14 / 2
Refine
x < 7

Part 2
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8 / 92 / 8
Refine
x < 23 / 2

7 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let X denote the heights of women in the USA.

It is provided that X follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

What is the expanded form of 709.104

andreev551 [17]

700 + 9 + .1 + .04

Hope this helps that the answer

5 0

3 years ago

Find the equation of the line between (7,−9) and (5,6) in slope intercept form.

poizon [28]

Set y=ax+b pass (7,-9) (5,6)
=》-9=7a+b
6=5a+b
=》2a=-15
a=-15/2
b=6-5a=6+37.5=43.5
=》y= -15/2(x)+43.5
2y+15x=87

5 0

3 years ago

Read 2 more answers