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2 years ago

Can someone plz help me on this plz I beg u

Mathematics

2 answers:

dexar [7]2 years ago

8 0

Answer:

10,120cm³

Step-by-step explanation:

Volume of pyramid formula:

$V = \frac{l*w*h}{3}$

l = length

w = width

h = height

Plug in the numbers:

V = 46*20*33/3

V = 10120

Debora [2.8K]2 years ago

8 0

Answer:

option D is the correct answer dude

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Help please !!!!!!!!!!!!

Anastasy [175]

Answer:

X=10 and

$y = 5 \sqrt{3}$

4 0

2 years ago

Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...

Ugo [173]

Answer:

$a_6_3=371$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

$-1,5,11,...$

Let

$a_1=-1\\a_2=5\\a_3=11$

$a_2-a_1=5-(-1)=5+1=6$

$a_3-a_2=11-5=6$

The common difference is $d=6$

We can write an Arithmetic Sequence as a rule

$a_n=a_1+d(n-1)$

where

a_n is the nth term

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

$n=63\\d=6\\a_1=-1$

substitute

$a_6_3=-1+6(63-1)$

$a_6_3=-1+6(62)$

$a_6_3=-1+372$

$a_6_3=371$

6 0

3 years ago

To find difference 7-3 5/12 how do you rename the 7

Nookie1986 [14]

7 would probably end up being 6 12/12 if I am doing his correctly.

4 0

2 years ago

Read 2 more answers

What is the equation of the line that passes through the points (-1, 7) and (2, 10) in Standard Form?

Usimov [2.4K]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{2-(-1)}\implies \cfrac{3}{2+1}\implies \cfrac{3}{3}\implies 1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}$

just to point something out, is none of the options, however -x + y = 8, is one, though improper.

3 0

2 years ago

Please solve this it’s about math

sineoko [7]

#3 - [D = (6 - 2)^2 + (4 - 1)^2] [] >> D= [Square root of} 16+9

So the awnser to #3 is - 5

3 0

3 years ago

￼ Can someone plz help me on this plz I beg u

Can someone plz help me on this plz I beg u