Answer:
It is paramount to notice that since we have word blocks and no address is separated then there are zero cache hits.Therefore the address sequence exhibits no temporal locality.
Check the attachment
Hope this helps!
° Suspectible to phosphor burn-in
° Has shorter life span
° Has poor reproductions of the color black
° Not the highest resolution as seen in LCD
°Has a weird shimmering or flickering effect
° Uses more electrical power
Because speed test is measuring your real-time network connection, Tests taken within a few minutes of each other might vary a little based on network congestion and available bandwidth.
Answer:
There is no short answer.
Explanation:
First let's create the string:
- alphabetString = "abcdefghijklmnopqrstuvwxyz";
The first half of the string using slice method can be written as:
- alphabetString.slice(0, 13);
The first half of the string using only the ending index can be written as:
- alphabetString.slice(-13);
When we put - at the start of the index number, the counting begins at the last element with -1 and goes backwards.
The second half of the string can be written as:
- alphabetString.slice(13,26);
The second half of the string using only the starting index can be written as:
- alphabetString.slice(13);
To get the every second letter in the string, we need a for loop:
- for( let x = 0; x < alphabetString.length(); x = x + 2){
alphabetString.slice(x);
}
To get the entire string in reverse, we can use the reverse method that is built-in:
- alphabetString.reverse();
To get the every third letter of the string, we can again use a for loop:
- for( let x = -1; x = -27; x = x - 3){
alphabetString.slice(x);
}
I hope this answer helps.
Answer:
idk I'm not sure cause yeah
