Let X be a normal random variable with mean 40 and standard deviation 2. Find P(X < 28).
1 answer:
Answer:
0
Step-by-step explanation:
Given :
Mean = 40 ; Standard deviation = 2
P(x < 28)
Obtain the Zscore :
Z = (x - mean) / standard deviation
P(Z < (28 - 40) / 2))
Z = (28 - 40) / 2
Z = - 12 / 2
Z = - 6
P(Z < - 6) = 0.000000
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Step-by-step explanation:
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