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2 years ago

12

Let X be a normal random variable with mean 40 and standard deviation 2. Find P(X < 28).

1 answer:

Vikki [24]2 years ago

5 0

Answer:

0

Step-by-step explanation:

Given :

Mean = 40 ; Standard deviation = 2

P(x < 28)

Obtain the Zscore :

Z = (x - mean) / standard deviation

P(Z < (28 - 40) / 2))

Z = (28 - 40) / 2

Z = - 12 / 2

Z = - 6

P(Z < - 6) = 0.000000

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