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QveST [7]
3 years ago
7

Pre-Cal - Someone please help! (Image Attached)

Mathematics
1 answer:
olasank [31]3 years ago
6 0
Note that \displaystyle{ \sin30^{\circ}= \frac{1}{2} and \displaystyle{ \cos30^{\circ}= \frac{ \sqrt{3}}{2}.

From the unit circle, we can check that \sin30^{\circ} and \sin(-30)^{\circ} have the same value, but opposite signs, that is:

\sin(-30)^{\circ}=-\sin(30)^{\circ}=-\frac{1}{2}. 


Thus, 
\displaystyle{ \cos(x-y)= \cos(-30^{\circ}-60^{\circ})=cos(-90^{\circ}).


Note that cos(-90^{\circ}) is the x-coordinate of the lowest point on the unit circle, that is (0, -1). Thus cos(-90^{\circ})=0


Answer: 0

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Hi algebra is hard please help: The expression (8x+ 4) inches represents the perimeter of a rectangle whose width is (3x − 4) in
Bess [88]

Answer:

Length = 4 inches

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

If x = 2

Perimeter = 8x - 4

= 8(2) - 4

= 16 - 4

= 12 inches

Width = 3x - 4

= 3(2) - 4

= 6 - 4

= 2 inches

Perimeter of a rectangle = 2(length + width)

12 = 2(length + 2)

12 = 2length + 4

12 - 4 = 2 length

8 = 2 length

Length = 8/2

Length = 4 inches

8 0
3 years ago
Taylor wants to center a 3.5 inch picture on a piece of paper that is 12 inches wide How
AVprozaik [17]

Answer:

The picture is 4.25 inches from the side of the paper

Step-by-step explanation:

- Taylor wants to center a 3.5 inch picture on a piece of paper that is

12 inches wide

- Lets think about that he want to put the picture in the center of the

paper, then divide the length of the paper into two equal parts and the

picture into two equal part

∵ The width of the paper is 12 inches

∵ 12 ÷ 2 = 6 inches

∵ The width of the picture is 3.5 inches

∵ 3.5 ÷ 2 = 1.75

- Now lets subtract from 6 inches (half paper) 1.75 inches (half picture)

to find the distance between the side of the paper and the picture

∵ 6 - 1.75 = 4.25

∴ The distance from the side of the paper to the picture is 4.25 inches

* <em>The picture is 4.25 inches from the side of the paper</em>

* Look to attached figure for more understand

7 0
3 years ago
Read 2 more answers
What are the typical null and alternate hypotheses for a significance test on slope?
Tju [1.3M]
I'm sure you should look it up on Google I'm pretty sure that that would help you more than this stupid app OK look it up on Google or a Siri it will help you a lot better
8 0
3 years ago
Rhonda took $20 with her to spend on popcorn and candy for herself and her friends at the movie theater. The price for each bag
MrRa [10]

The linear equation that represents the scenario is 5x + 2.5y = 20

<h3>How to determine the equation?</h3>

The given parameters are:

  • Popcorn = $5 per bag
  • Candy = $2.5 per bag i.e. half the price of pop corn

Let x represents popcorn and y represents candy.

So, we have:

5x + 2.5y = 20

The intercepts in this case are the maximum number of candy and popcorn Rhonda can buy

See attachment for the graph

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

5 0
2 years ago
PLZZZZZZZZZ HELP THERE IS JUST THIS ONE AND IM STILL CONFUSED PLZZZ HELPPPP ME REAL QUICK ITS REALLY EASY
RUDIKE [14]
Angle a is 22.62 degrees
and
angle b is 67.38 degrees

7 0
3 years ago
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