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Arlecino [84]
3 years ago
5

What two numbers multiply to -42 but also add up to -11

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:

-14 *3 and -14 + 3

Step-by-step explanation:

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Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship
yan [13]

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

6 0
1 year ago
A slow pitch softball diamond is actually a square 60 ft on a side. how far is it from home to second ​base?
krek1111 [17]
For this case we have a square whose sides are known and equal to 60 ft.
 We want to find the diagonal of the square.
 For this, we use the Pythagorean theorem.
 We have then:
 d^2 = 60^2 + 60^2

d =  \sqrt{60^2 + 60^2}

 d =  \sqrt{3600 + 3600}

d = \sqrt{2*3600}

d = 60\sqrt{2}

 Answer:
 
from home to second ​base it is about:
 d = 60\sqrt{2} feet
3 0
3 years ago
A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Explain how to use a graph of the function f(x) to<br> find f(3).
Oksanka [162]

To find the value of f(3) we need to follow the below steps :

Step 1 : First plot the graph of f(x)

Step 2 : We need to find f(3) or the function value at x = 3 therefore, in the graph locate the point (3,0)

Step 3 : Draw a line parallel to Y-axis passing through the point (3,0) .

Step 4 : Now there exists two cases :

If the drawn line do not intersect the graph of f(x), then no value of f(3) exists for the given function of x

If the drawn line intersects the graph, then the intersection point is marked and a line parallel to x - axis is drawn passing through that marked or intersection point. And the line where it intersects the y - axis is our required value of f(3).

If this is wrong than I guess I wasn't smart enough :)

4 0
2 years ago
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