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Arlecino [84]
3 years ago
5

What two numbers multiply to -42 but also add up to -11

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:

-14 *3 and -14 + 3

Step-by-step explanation:

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2t-7-5t=11 what is the answer
Verizon [17]
<span>2t-7-5t=11

Start by combing like terms:

2-5t=-3t  

Now we have: 

-3t-7=11  

Add 7 to both sides

-3t=18

To isolate t we divide both sides by -3 

Final answer: 
t=-6 </span>
3 0
3 years ago
What is the measure of this angle?<br> A) 44° <br> B) 56° <br> C) 136° <br> D) 144°
allsm [11]
A) 44 degrees just look at the degree the line segment lands on in the protractor
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3 years ago
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Doug says that this clock shows 8:43.is he correct? Explain why or why not
Lena [83]
Depending on what the clock says yes and no.
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3 years ago
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Model with mathematics. A bus can hold no more than 86 students. Write an inequality to describe the situation. - Graph the ineq
ki77a [65]

Answer:

x less than or equal to 86

Step-by-step explanation:

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8 0
2 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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