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spin [16.1K]
3 years ago
14

Find the GCF of 12x^4y, 16xy^2, and 20y^3

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

12x^4y^ = 2 * 2 * 3 * x^4*y\\\\16xy^2 = 2*2*2*2*x* y^2\\\\20y^3 = 2*2*4*y^3\\\\GCF = 2 * 2 * y=4y

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Find the x- and y- intercepts of parabola y=5x^2-16x+10
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Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
1 year ago
If a truck gets 14 mile to the gallon on average, how much does carbon dioxide is emitted into the atmosphere when the truck tra
Masja [62]
Converting 200 miles to the amount of carbon dioxide emission that would be 1.884 tons annually. This will be the amount of carbon dioxide given that 200 miles is monthly covered.
8 0
2 years ago
Read 2 more answers
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MAVERICK [17]

Answer:

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Step-by-step explanation:

3/4 · k hours: 4/7 · k dresses for any constant k

If we want 1 hour, then k will need to be 4/3

4/3 × 4/3 hours: 4/7 × 4/3

1 hour = 16/21 dresses

7 0
3 years ago
Find the limit, if it exists.<br> Picture provided below.
Alja [10]

The answer is 20 because you plug in x=2 into f(x)

3 \times 2 {}^{3}  + 2^{2}  - 8 = 20

7 0
3 years ago
Can we please have some help
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2 years ago
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