A box has 6 sides so you multiply 16.7 and 6 and you’ll get 100.2
ANSWER IS 100.2in
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Answer:
The equation for finding the hypotenuse is:
c^2+c^2=h^2
For example, in the first exercise:
8^2+10^2=164^2
For clearing the equation, find out the root of 164=
12.8
Hypotenuse of the first triangle is 12.8!
Let me help you with the next, if you still dont get it:
8^2+13^2=233^2
Root of 233: 15.2
Hypotenuse of second triangle is 15.2!
Answer:
Population, well, it is recorded as partners and 642x153=98226 is calculated correctly, you divided by 2 which is 98226 divided by 2 is 49113.
