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Ahat [919]
2 years ago
5

Find the equation of the horizontal line passing through the point (3,6)

Mathematics
2 answers:
lutik1710 [3]2 years ago
8 0

Answer: Y = 6

Step-by-step explanation: The equation is this because when you put this equation on a graph, it makes a horizontal line passing through (3,6). When an equation is like Y = 6 it will make a horizontal line on that coordinate of Y, but if it is X = 6 it will make a vertical line on the coordinate of X.

S_A_V [24]2 years ago
7 0

Answer:

This might help

Step-by-step explanation:

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sukhopar [10]
2(z-10)=-4
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3 0
3 years ago
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A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving
sergey [27]

Answer:

The continuous yearly interest is  22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

A=Pe^{rt}

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

\therefore 110,000= 4,700e^{r\times 14}

\Rightarrow e^{14r}= \frac{110,000}{4,700}

Taking ln both sides

\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})

\Rightarrow {14r}= ln(\frac{1100}{47})

\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}

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4 0
3 years ago
Which is different? Find "both" answers.
Alina [70]
B & C would be your answer because 3^-3 would turn into a fraction, 1/3^3 which is the same as C.
8 0
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Evaluate find the degree of a polynomial (y³-2)(y²+11)​
jasenka [17]

Answer:

5

Step-by-step explanation:

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= y^3 (y^2 +11)-2(y^2 +11)

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Here, highest power of the variable is 5.

Therefore, degree of the given polynomial is 5.

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neonofarm [45]

Answer: A

Step-By-Step Explanation: if n is greater than or equal to 2 is an add integer then the domain of: f(x)-x^2+8 is the solution to the inequality 2+8 greater than or equal to 0. which of the following statements is true?

3 0
1 year ago
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