Answer: ∑Tₓ = 201.222
time required to complete the last two units is 201.222 minutes
Explanation:
Given that,
total time required to four units is 600 hours,
Learning curve applied is 75% and from the learning curve coefficient table, total time factor to complete four units at 75% learning curve is 2.946
so
∑Tₙ = T₁ × total time factor
{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }
we substitute
∑T₄ = ∑T₁ × total time factor
600 = ∑T₁ × 2.946
∑T₁ = 600/2.946
∑T₁ = 203.666 minutes
Now to get the total time required to complete 6 units, we say:
∑T₆ = ∑T₁ × total time factor
Note that total time factor at this point changes;
( from the learning curve coefficient table, total time factor to complete 6 units at 75% learning curve is 3.934)
so we substitute
∑T₆ = 203.666 × 3.934
∑T₆ = 801.222
Now to find how long should it take them to finish the last two units, we say
∑Tₓ = ∑T₆ - ∑T₄
∑Tₓ = 801.222 - 600
∑Tₓ = 201.222
Therefore time required to complete the last two units is 201.222 minutes
