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lilavasa [31]
3 years ago
13

UA Hamburger Hamlet (UAHH) places a daily order for its high-volume items (hamburger patties, buns, milk, and so on). UAHH count

s its current inventory on hand once per day and phones in its order for delivery 24 hours later. Determine the number of hamburgers UAHH should order for the following conditions:
Average daily demand 600
Standard deviation of demand 100
Desired service probability 99%
Hamburger inventory 800
Business
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

730 items

Explanation:

The objective of the given information is to determine the number of hamburgers UAHH should order for the following conditions:

Average daily demand 600

Standard deviation of demand 100

Desired service probability 99%

Hamburger inventory 800

The formula for a given order quantity in a fixed period of time can be expressed as :

q = \overline d(L+T)+ z \sigma_{L+T}-I

where;

q =  order quantity = ???

\overline d = daily demand average = 600

L = lead time in days = 1

T = time taken = 1

z = no of standard deviation = ???

\sigma_{L+T} = standard deviation of usage in lead time and time taken = ???

I = present inventory level = 800

\sigma_{L+T} = \sqrt 2 × standard deviation of daily demand

\sigma_{L+T} = \sqrt{2} *100

\sigma_{L+T} = 1.4142 * 100

\sigma_{L+T} = 141.42 items

From the Desired service probability 99% = 0.99; we can deduce the no of standard deviation by using the excel function (=NORMSINV (0.99))

z = 2.33

From q = \overline d(L+T)+ z \sigma_{L+T}-I

q =600(1+1)+ 2.33*(141.42)-800

q =600(2)+ 2.33*(141.42)-800

q =1200+329.5086-800

q = 729.5086 items

q ≅ 730 items

Therefore; the  number of hamburgers UAHH should order from the following given conditions = 730 items

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