Answer:
x^9
----------------
125 y^12
Step-by-step explanation:
(5x^-3 y^4)^-3
We know that (ab)^c can be split into a^ * b^c
5^-3 *x^-3 ^-3* y^4 ^-3
We also know that a^b^c = a^ (b*c)
5^-3 *x^(-3 *-3) * y^(4 *-3)
5^-3 *x^(9) * y^(-12)
We know that negative exponents in the numerator move it to the denominator. The exponent stays the same except for the negative.
1/5^3 * x^9 * 1/ y^12
We know that 5^3 = 125
Rearranging the order
Answer: x = 4; x = 5
The directions specify to solve by factoring
x^2 - 9x + 20 = 0
To factor, find two numbers that add to -9 and multiply to 20
-5 and -4 work
-5 + (-4) = -9
-5 * -4 = 20
(x - 4)(x - 5) = 0
x = 4, x =5
papá fríoStep-by-step explanation:
<u>Answer:</u>
<u>Steps:</u>
(13⁰/5)²
(1÷5)²
1²÷5²
1÷25
