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erastovalidia [21]
3 years ago
8

What is "7/4 as a mixed number?A. 13/4B. 1/4C. 3/4D. 1'/4​

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

actually it's neither it's really 1 and 3/4

Step-by-step explanation:

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Which equation will have no solution for x? *
Tatiana [17]

Answer: its 5

Step-by-step explanation: 2 plus 2 plus 1 eqael 5 hehehehe

5 0
2 years ago
How do you solve this using system of equations <br> y = 3x -1 <br> y = -x +3
Allisa [31]

Answer:

1

Step-by-step explanation:

The first equation's y value can be replaced with -x + 3, then solve it:

3x - 1 = -x + 3

3x + x = 3 + 1

4x = 4

x = 4 divided by 4

x = 1

4 0
2 years ago
Read 2 more answers
A rectangle has a perimeter of 41.1 and the width is half the length
Julli [10]
Perimeter=2(w+l)
=2(3w)
=6w
41.1=6w
w=6.85

7 0
3 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
How do you solve<br> 9/y = 12?<br> This is a two step equation
NARA [144]

Answer:

108

Step-by-step explanation:

12x9=108

108/9 = 12

8 0
2 years ago
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