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1 year ago

The equation y – 2 = 3(x + 1) is in point-slope form. Which is the slope-intercept form?

Mathematics

2 answers:

S_A_V [24]1 year ago

5 0

y = 3x + 5

Step-by-step explanation:

Solution Given:

equation is

y-2=3(x+1)

opening bracket

y-2=3x+3

adding 2 on both side

y-2+2=3x+3+2

y=3x+5

y=3x+5 is the slope-intercept form.

neonofarm [45]1 year ago

4 0

Answer:

y = 3x + 5

Step-by-step explanation:

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How to flip a desk 5 feet long and then flip another desk and it was 10 feet long what would be the answer

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I think this may be multiplication so 5 times 10 equls50

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3 years ago

Customer account numbers for a certain company consists of 3 letters followed by 5 numbers how many different account numbers ar

Arturiano [62]

Answer:

1,757,600,000

Step-by-step explanation:

company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.

We have 26 lettrs and 10 digits

So, the possible out comes for each one of the letters = 26

And the possible out comes for each one of the numbers = 10

∵ repetitions of letters and digits are allowed.

So, the possible accounts are = 26³ * 10⁵ = 1,757,600,000

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3 years ago

Plant B is 6 2/3 inches tall. and C is 4 4/15 inches tall. Complete the sentences and show your reasoning

artcher [175]

Answer:

Plant C is 0.64 times as tall as Plant B

Plant C is 2.4 inches shorter than Plant B

Step-by-step explanation:

Plant B is 6 2/3 inches tall. Plant B is 20/3 inches tall.

Plant C 4 4/15 inches tall. Plant C is 64/15 inches tall.

a.) Plant C is shorter than Plant B $= \frac{64}{15} \times \frac{1}{\frac{20}{3} } = \frac{64}{15} \times\frac{3}{20} = \frac{16}{25}$ = 0.64 times.

b.) Plant C is shorter than Plant B by = $\frac{20}{3} - \frac{64}{15} = \frac{100}{15} - \frac{64}{15} = \frac{100 -64}{15} = \frac{36}{15} = 2\frac{2}{5} = 2.4$ inches

3 0

3 years ago

The longest side is 24cm and the second-longest side is 20cm what is the length of the shortest side?

lakkis [162]

13.3cm rounded to the nearest 10th

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3 years ago

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

3 years ago