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igor_vitrenko [27]
3 years ago
13

Solve this system by ELIMINATION!9x-12y=15 -4x+4y=0​

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

x = -5

y = -5

Step-by-step explanation:

here's the solution :-

multiply equation (2) with 3

we get,

=》9x - 12y = 15

=》-12x + 12 y = 0

by adding the equations, :-

=》9x - 12y - 12 x + 12y = 15 + 0

=》-3x = 15

=》x = 15 ÷ -3

=》x = -5

putting the value of x as -5 in equation (2)

=》-4x + 4y = 0

=》( -4 × -5 ) + 4y = 0

=》20 + 4y = 0

=》4y = - 20

=》 y = -20 ÷ 4

=》y = -5

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let's firstly convert the mixed fractions to improper fractions and then to do away with the denominators, let's multiply both sides by the LCD of all denominators.

\stackrel{mixed}{1\frac{3}{4}}\implies \cfrac{1\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{7}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{4}-\cfrac{4}{5}=\cfrac{35}{20}-\boxed{?}\implies \stackrel{\textit{multipling both sides by }\stackrel{LCD}{20}}{20\left( \cfrac{7}{4}-\cfrac{4}{5} \right)=20\left( \cfrac{35}{20}-\boxed{?} \right)} \\\\\\ 35-16=35-20\boxed{?}\implies 19=35-20\boxed{?}\implies -16=-20\boxed{?} \\\\\\ \cfrac{-16}{-20}=\boxed{?}\implies \cfrac{4}{5}=\boxed{?}

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3 years ago
Read 2 more answers
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