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Law Incorporation [45]
3 years ago
14

If a pedigree showed that more male offspring had a trait than female offspring, what could that tell you about the trait?

Biology
1 answer:
dalvyx [7]3 years ago
8 0
That means that the males were carries, and that’s the male offsprings past generations had people with the trait
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If a person with type o blood is crossed with a person who is heterozygous for type b blood, what would be the predicted phenoty
Svetradugi [14.3K]
Wouldnt it be O? im not to sure

5 0
3 years ago
Processing of the mRNA begins before transcription of eukaryotic mRNA\'s is complete. The end of the mRNA is prepared for recogn
kompoz [17]

Answer:

The correct answer is

1. 5' end.

2. guanosine

3. 5′ to 5′ triphosphate linkage.

4. On the 7th position.

5. 2′ hydroxy-groups of the first 2 ribose sugars.

Explanation:

The eukaryotic mRNA is processed or modified with a guanosine cap at 5' end and poly-A tail at 3'end before translation.

The process of adding a cap at 5' end of a growing mRNA is known as capping. The process of capping adds guanosine nucleotide at the 5'-end of mRNAs by 5′ to 5′ triphosphate linkage. This guanosine is modified by methylating at the  7th position of the atom. The mRNA is further modified by methylation of first two ribose sugars at their 2′ hydroxy-groups. This capping is advantageous to the sequence as it protects the end from phosphatases and nucleases.

5 0
3 years ago
Assignment: Distinguishing Phyla Exploration
Vaselesa [24]

Answer:

I am pretty sure that it is Vertebrates for the first question.

6 0
3 years ago
Select the variables that you would predict to be regulated by the body using a homeostatic mechanism.
erik [133]
The variables that i would predict to be regulated by the body using a homeostatic mechanism are; amount of pressure which moves fluids in the body; amount of heat in the body; amount of water in the body;
Homeostasis is best described as the maintenance of a stable internal environment in spite of a changing external environment. 
8 0
3 years ago
An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this
goblinko [34]

Answer:

Option B

Explanation:

Given

Number of incidences or frequency of an autosomal recessive disease = \frac{1}{10000}

As per Hardy Weinberg's equation, frequency of a recessive genotype is q^{2}

q = \sqrt{\frac{1}{10000} }\\ q = \frac{1}{100}

As per first equation of Hardy Weinberg's -

p+q=1

so ,

p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}

p^2 = (\frac{99}{100})^2\\p^2 =\frac{9801}{1000}

As per second equation of Hardy Weinberg's -

p^{2} + q^{2} + 2pq=1

Substituting the given values in above equation, we get -

\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1%

2pq = \frac{1}{100}

Hence, option B is correct.

8 0
3 years ago
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