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ZanzabumX [31]
1 year ago
10

If f(x) = x5 â€" 1, g(x) = 5x2, and h(x) = 2x, which expression is equivalent to [g o f o h](9)? 2(5(95 â€" 1)2) 2((5 · 92)5 â€

" 1) 5((2 · 9)5 â€" 1)2 (5(2 · 9)2)5 â€" 1
Mathematics
1 answer:
Elina [12.6K]1 year ago
6 0

The equivalent expression for [gofoh](9) is 5(32(9)^5-1).

According to the given question.

We have three functions

f(x) = x^5 - 1

g(x) = 5x^2

h(x) = 2x

Here, we have to find the equivalent expression for [gofoh](9).

so,

gofoh(x)

= g((2x)^5 -1)

= g(32x^5 -1)

= 5(32x^5 -1)

Therefore,

gofoh(9)

= 5(32(9)^5-1)

Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).

Find out more information about equiavlent expression here:

brainly.com/question/28170201

#SPJ4

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\\ \\ =\frac { { \left( 25{ a }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  } }{ { 4 }^{ \frac { 1 }{ 2 }  } } \\ \\ =\frac { \sqrt { 25{ a }^{ 2 } }  }{ \sqrt { 4 }  } \\ \\ =RHS
6 0
3 years ago
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The area of a circle is 77.28m2.<br> Find the length of the diameter rounded to 1 DP.
allochka39001 [22]

Answer:diameter=9.92m

Step-by-step explanation:

Area=77.28

π=3.14

Area=π x (d/2)^2

77.28=3.14 x (d/2)^2

Divide both sides by 3.14

77.28/3.14=(3.14x(d/2)^2)/3.14

24.6=(d/2)^2

Take them square root of both sides we get

d/2=√(24.6)

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d=4.96 x 2

d=9.92

4 0
2 years ago
Guys help me with System of linear equations:
Leni [432]

Step 1: Add the two equations together to get just one equation.

2x + y + x - y = 5 + 1

Step 2: Simplify.

3x = 6

Step 3: Divide by 3 on both sides.

3x / 3 = 6 / 3

x = 2

Therefore, the answer is x=2


6 0
3 years ago
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In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

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3 0
3 years ago
Please help me with my homework
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Answer:

x=90 y=58 z=32

Step-by-step explanation:

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