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ZanzabumX [31]
2 years ago
10

If f(x) = x5 â€" 1, g(x) = 5x2, and h(x) = 2x, which expression is equivalent to [g o f o h](9)? 2(5(95 â€" 1)2) 2((5 · 92)5 â€

" 1) 5((2 · 9)5 â€" 1)2 (5(2 · 9)2)5 â€" 1
Mathematics
1 answer:
Elina [12.6K]2 years ago
6 0

The equivalent expression for [gofoh](9) is 5(32(9)^5-1).

According to the given question.

We have three functions

f(x) = x^5 - 1

g(x) = 5x^2

h(x) = 2x

Here, we have to find the equivalent expression for [gofoh](9).

so,

gofoh(x)

= g((2x)^5 -1)

= g(32x^5 -1)

= 5(32x^5 -1)

Therefore,

gofoh(9)

= 5(32(9)^5-1)

Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).

Find out more information about equiavlent expression here:

brainly.com/question/28170201

#SPJ4

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At first we need to know how to find the distance between two parallel lines
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If we have two parallel lines ⇒ y₁ = mx + c₁   and    y₂ = mx + c₂
So, the distance between y₁ and y₂ = d = \frac{|c_{1} - c_{2}|}{\sqrt{1 + m^{2}}}
========================================================

Part (1):
=======

<span>The distance between the lines
</span>
<span> Y₁ = 3x + 10    and       Y₂ = 3x - 20</span>
∴ m = 3  , c₁ = 10  and  c₂ = -20
∴ d = \frac{| 10 - (-20)|}{\sqrt{1 + 3^{2}}}= \framebox{9.5}

========================================================

Part (2):
=======

<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span>    and       Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5  , c₁ = 3/2 = 1.5   and  c₂ = -5
∴ d = \frac{| 1.5- (-5)|}{\sqrt{1 + 1.5^{2}}}= \framebox{3.6}

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