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ZanzabumX [31]
1 year ago
10

If f(x) = x5 â€" 1, g(x) = 5x2, and h(x) = 2x, which expression is equivalent to [g o f o h](9)? 2(5(95 â€" 1)2) 2((5 · 92)5 â€

" 1) 5((2 · 9)5 â€" 1)2 (5(2 · 9)2)5 â€" 1
Mathematics
1 answer:
Elina [12.6K]1 year ago
6 0

The equivalent expression for [gofoh](9) is 5(32(9)^5-1).

According to the given question.

We have three functions

f(x) = x^5 - 1

g(x) = 5x^2

h(x) = 2x

Here, we have to find the equivalent expression for [gofoh](9).

so,

gofoh(x)

= g((2x)^5 -1)

= g(32x^5 -1)

= 5(32x^5 -1)

Therefore,

gofoh(9)

= 5(32(9)^5-1)

Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).

Find out more information about equiavlent expression here:

brainly.com/question/28170201

#SPJ4

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Which expression represents a number n increased by 18
liraira [26]

Answer:

n+18

Step-by-step explanation:

A number n just means a variable n, and since we are increasing it (or adding to it), by 18, it is n+18

4 0
2 years ago
Joe is a waiter at a local pizza parlor. he usually gets a tip from the tables he waits on. the bill for one table comes to $34w
Lilit [14]

Answer:

t=p*34

Step-by-step explanation:

t=p*T, where T is the bill for the table Joe waited on, p is the percent tip and t is the tip left for the waiter

In this situation, the bill is 34, so lets plug that in

t=p*34

7 0
3 years ago
A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January
Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that p = 0.23

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084

P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735

P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439

P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109

P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

E(X) = np = 10*0.23 = 2.3

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33

The expected number is 2.3 and the standard deviation is 1.33.

5 0
3 years ago
Identify whether the series summation of 12 open parentheses 3 over 5 close parentheses to the I minus 1 power from 1 to infinit
Finger [1]
∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]

Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.

Sum = 12/(1 - 3/5) = 12/(2/5) = 30.
3 0
2 years ago
Solve angle X to 1 dp
geniusboy [140]

Answer:

x ≈ 57.8°

Step-by-step explanation:

using the Sine rule in the triangle

\frac{11}{sinx} = \frac{8}{sin38} ( cross- multiply )

8 × sinx = 11 × sin38° ( divide both sides by 8 )

sinx = \frac{11sin38}{8} , then

x = sin^{-1} ( \frac{11sin38}{8} ) ≈ 57.8° ( to 1 dec. place )

7 0
2 years ago
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