Answer:
Its the first option.
Step-by-step explanation:
Game 1 - you win or lose.
Game 2 - you win or lose
So that makes 4 possible branches along the tree.
WW, WL LW and LL.
4x - 3y = -11
-7x - 8y = 6
We need to cancel out one of the variables so let's multiply the first equation by 8 and the second by 3 and aim to cancel y.
32x - 24y = -88
-21x - 24y = 18
Now we subtract,
53x = -106
x = -2
3y = 4x + 11 = 4(-2) + 11 = 3
y = 1
Answer: (x,y)=(-2,1)
Check:
4(-2) -3(1) = -8 - 3 = -11, good
-7(-2) - 8(1) = 14 - 8 = 6, good
Lets use x to represent the cheese wafers and y to represent the chocolate wafers.
For part A:
The system of equation would be:
x+y=20 (this equation represents how many were bought)
2x+y=25 (the price. Remember that there is an imaginary 1 in front of the y)
For Part B:
To find how many chocolate wafers were bought, isolate y in the first equation (x+y=20) by bringing y to the other side. You are left with x= 20-y.
Plug the new equation into the second equation (2x+y=25) for x.
Now solve:
Step 1 (Plug in): 2(20-y)+y=25
Step 2 (Distribute): 40-2y+y=25
Step 3 (Combine like terms): 40-y=25
Step 4 (Subtract 40 from each side of the equation): -y=-15
Step 5 (divide by -y): y=15
Therefore, a total of 15 chocolate wafers were bought. This means that a total of 5 cheese wafers were bought. I got the answer by solving for variables. I selected these particular method, because it is the easiest and most efficient way of solving this problem (in my opinion). Hope I help :). If you have any questions please let me know.
C because rise over run. Rise being the X-axis and Run being then Y-axis.
I believe 35152 people watched both teams play