1. Acceleration is the rate of change of velocity, so is the slope of a velocity vs. time curve (which you are given here). The curve is not a straight line, so its slope is changing. Points on the right of the curve are higher than points on the left, so the slope is positive. The appropriate choice is
... changing positive acceleration
2. Units conversion is required.
The appropriate choice is
... 0.673 m/s²
3. As before, the slope of the curve is the acceleration. This curve goes up less than 1 m/s for each second horizontally, so the appropriate choice is
... 0.6 m/s²
False.
The applicable formula for amount in account (a) after t years is given by:
a = Pe^(rt); where a = Amount in an account, P = Amount deposited, r = Annual interest rate, t = time in years.
Substituting;
a = 3000e^(0.055t)
Its B. <span>People who shop in bookstores are likely to read more books than those who do not.</span>
Here, in order to find the solutions to the quadratic equation - x² + x - 30 = 0, we will use factorization method.
In the method, we will split 30, in such factors, which when added or subtracted gives us 1, and when multiplied gives us -30.
So, we will use, -5 and 6. When they are added they will give us 1 and when multiplied they will give us -30 as answer.
Now, the equation will be written as -
x² - 5x + 6x - 30 = 0
Taking common, we get
x(x - 5) +6(x-5) = 0
(x-5)(x+6) = 0
So, x - 5 = 0 and x +6 = 0, we will get, x = 5 and x = - 6
<u>Thus, the correct option is C). x = 5 and -6</u>
Given that
(2+i)²/(3+i)
On multiplying both numerator and the denominator with (3-i) then
⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]
⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]
⇛ [(2+i)²(3-i)]/[(3²-i²)
⇛ [(2+i)²(3-i)]/(9-i²)
⇛ [(2+i)²(3-i)]/[9-(-1)]
Since ,i² = -1
⇛ [(2+i)²(3-i)]/(9+1)
⇛ [(2+i)²(3-i)]/10
⇛ [{2²+i²+2(2)(i)}(3-i)]/10
⇛ (4+i²+4i)(3-i)/10
⇛ (4-1+4i)(3-i)/10
⇛ (3+4i)(3-i)/10
⇛ (9-3i+12i-4i²)/10
⇛ (9+9i-4(-1))/10
Since, i² = -1
⇛(9+9i+4)/10
⇛(13+9i)/10
⇛ (13/10)+ i (9/10)
We know that
The conjugate of a+ib is a-ib
So,
The conjugate of (13/10)+ i (9/10) is
(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)
<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)
<em>Additional</em><em> comment</em><em>:</em>
- The conjugate of a+ib is a-ib and
- i = -1
- (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².
