1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldenfox [79]
3 years ago
13

This question tho?.....​

Mathematics
1 answer:
fomenos3 years ago
4 0
I think the answer is The third one
You might be interested in
PLEASE HELP!!! here are two different strategies to find the new price of a hat after a discount of 40%. The hat was originally
Yakvenalex [24]

Answer:

Step-by-step explanation:

Method 1: Calculate 40% discount on original price, then subtract discount from original price.

Amount of discount = 40% of $30

= 0.40 × $30

= $12

New price = $30 - $12 = $18

Method 2:

New price = (100% - discount percentage) of original price

= 60% of original price

= 0.60 × $30

= $18

6 0
3 years ago
Alright I need The answers for number 27 please reply To This question I posted
lys-0071 [83]

Answer:

C. Sqrt(12^2+9^2)

Step-by-step explanation:

Pythagorean theorem is

x^2+y^2=z^2

So solving for z

z=sqrt(x^2+y^2)

z=sqrt(9^2+12^2)

6 0
4 years ago
Perform the following operation
Cerrena [4.2K]

Answer:

When you multiply an odd number of negatives you get a negative result. When you multiply an even number of negatives you get a positive result.

First, multiply normally.

25x10x5

1100

Then determine whether the sign is positive or negative. Since there is an odd number of negatives, the sign is negative.

So, the answer is -1100.

:)

7 0
3 years ago
If AVB has a measure of 70 and VM is its angle bisector, what is the measure of AVM
maw [93]
I think  AVM= 35 degrees 
Hope this helps 
8 0
3 years ago
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
Other questions:
  • James filled 4 glasses with milk. Patrick filled 6 glasses with milk. Each glass held 8 ounces of milk. Which method explains a
    15·1 answer
  • I need help thank you
    13·1 answer
  • Which expression could be used to solve this problem?
    14·2 answers
  • How to solve the problem
    9·1 answer
  • A car dealer paid a certain price for a car and marked it up byt 7/5 of the price he paid. Later he sold it for 24000. What is t
    8·1 answer
  • Factor completely 2x^3 + 14x^2 + 6x + 42.
    6·1 answer
  • Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $30,
    7·1 answer
  • Evaluate the expression 2x^2-y^1+3x^0 for x=3 and y=7
    10·2 answers
  • A hybrid car can travel 40 miles per gallon. Approximately how many gallons of fuel will the car need to travel 20 km? (5 points
    14·1 answer
  • PLEASE HELP
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!